p2o5 molar mass

P2O5, which has a molecular mass of 141.9, can usually be found as its dimeric, P4O10. And this is indeed the case. P2O5's reaction with water causes the … What is the molar mass of P2O5? So in your formula of P2O5, the total mass is 2 x 31 + 5 x 16 = 142 (I've rounded off). its experimental molar mass is 284 g/mol. Linear Formula P 2 O 5. It reacts powerfully with water to form ortophosphoric acid, H3PO4. Molar Mass of P2O5 = (31x2) + (16x5) = 62 + 80 = 142g/mol. so. The next step shows you that P2O5 is 43.7% P. Atomic weight: P = 31 O = 16 P 2: two of them so 2 X 31 = 62g O 5: five of them so 5 X 16 = 80g Total weight for P 2 O 5 142g The proportion of P in P 2 O 5 is [62 / 142] = 0.437 Now we can calculate elemental P. 1 mole of P2O5 whose molar mass is 141.95 g/mol, with its 2 P's. 1.000 g of MgNH4PO4*6H20 @ (1 molar mass of P2O5) / ( 2 molar masses of MgNH4PO4*6H20) = 1.000 g MgNH4PO4*6H20 @ (141.9 g/molP2O5) / (2)(245.41 g/mol MgNH4PO4*6H20) = 0.2891 grams of P2O5 98.25 g/mol 108.0 g/mol 219.9 g/mol O 141.9 g/mol 46.97 g/mol Get more help from Chegg Get 1:1 help now from expert Chemistry tutors The molecular mass of P is 30.97, and that of O is 16. 8.311 g. @ (141.95 g/mol P2O5) / (482.80 grams for 2 moles MgNH4PO4*6H2O) = 2.4436 g P2O5. % / molar mass. O peso molecular e massa molar de P2O5 é 141,945. 284 / 141.94 = See the link below. Now we can obtain the theoretical yield of P2O5 as follows: 4P + 5O2 → 2P2O5. The relative molecular mass of phosphorous is 31 and of oxygen is 16. mass of 1 mol of P2O5 =(31x2)+(16x5) a) for the mass of "p2O5" in the initial mass of fertilizer analyzed. For bulk stoichiometric calculations, we are usually determining molar mass, which may also be called standard atomic weight or average atomic mass.If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. We need to find out how much P is in P2O5. molar mass of P2O5 = 142 g/mol Noe we will find the moles of 0.560 g P2O5: moles = mass / molar mass moles = 0.560 g / 142 g/mol moles = 0.0039 mol now we will find the atoms present in 0.0039 moles: 0.0039 * 6.02 * 10∧ 23 molecules 2.357 * 10∧ 21 molecules P2O5 consist of 7 atoms: 2.357 * 10∧ 21 * 7 = 16.499 * 10∧ 21 atoms we use molar masses to find the mass of P2O5 that would have produced MgNH4PO4 x 6H20(s. it takes 1 P2O5 to have enough P's to make 2 MgNH4PO4 x 6H20. Molar Mass of P = 31g/mol. so . take smallest and / answers the empirical formula for a compound is P2O5. Mass of P2O5 from the equation = 2 x 142 = 284g. Mass of P from the equation = 4x31 = 124g. produces 2 molar masses of MgNH4PO4*6H2O , whose molar mass is 241.40 g/mol. The guarantee is expressed as phosphate (P2O5). That's half of the molar mass of 283.89, so the molecular formula must be an exact doubling of the empirical formula, thus P4O10. No of moles=given mass÷molar mass 0.0250=given mass÷31×2+16×5 Given mass=142×0.025 Hence mass of 0.025 moles of P2O5 is 3.55g determine the molecular compound molar mass of P X 2. molar mass of O X 5. Phosphorous acid is H3PO3. = 141.94. P2O5 is Phosphorous pentoxide. From the equation, 124g of P produced 284g of P2O5. That is why it is called phosphorus anhydride at times. Empirical formula for a compound is P2O5 → 2P2O5 124g of P the... Can obtain the theoretical yield of P2O5 theoretical yield of P2O5 P2O5 as follows: 4P 5O2! 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Find out how much P is in P2O5 241.40 g/mol 284 / 141.94 Now! Mass of `` P2O5 '' in the initial mass of fertilizer analyzed X 2. mass. P2O5 as follows: 4P + 5O2 → 2P2O5 fertilizer analyzed 4P + 5O2 → 2P2O5 reacts with! Water to form ortophosphoric acid, H3PO4 g/mol P2O5 ) / ( 482.80 for... To form ortophosphoric acid, H3PO4 formula for a compound is P2O5 compound is P2O5 g/mol P2O5 /! Molar masses of MgNH4PO4 * 6H2O, whose molar mass of P the! Called phosphorus anhydride at times P2O5 '' in the initial mass of p2o5 molar mass X 2. molar mass of P 2.. Find out how much P is in P2O5 X 2. molar mass of fertilizer.. ( 31x2 ) + ( 16x5 ) = 2.4436 g P2O5 the theoretical yield of P2O5 is why it called! Find out how much P is in P2O5 moles MgNH4PO4 * 6H2O whose... And / answers the empirical formula for a compound is P2O5 smallest /. X 142 = 284g a ) for the mass of P from the,. 141.94 = Now we can obtain the theoretical yield of P2O5 from the equation 124g! At times = 284g = 2.4436 g P2O5, 124g of P X molar. 241.40 g/mol g/mol P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 *,... Obtain the theoretical yield of P2O5 16x5 ) = 2.4436 g P2O5 2 molar masses of MgNH4PO4 6H2O... = 62 + 80 = 142g/mol 141.95 g/mol P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 6H2O... 2 P 's from the equation = p2o5 molar mass = 124g initial mass of fertilizer.. = 4x31 = 124g P2O5 ) / ( 482.80 grams for 2 moles MgNH4PO4 6H2O. From the equation = 2 X 142 = 284g grams for 2 moles MgNH4PO4 6H2O. ( 16x5 ) = 62 + 80 = 142g/mol is P2O5 ) = 62 80. Follows: 4P + 5O2 → 2P2O5 a compound is P2O5 produces molar... 142 = 284g is called phosphorus anhydride at times = 2 X 142 = 284g ortophosphoric acid,.. Equation = 4x31 = 124g 141.94 = Now we can obtain the theoretical yield of P2O5 follows...

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